John from Pa. Working towards my mcse. i enjoy kidding around, and look forward to meeting fellow nerds.

Rob I do try to take things at face value. I went back over what has been said and haven't found where you or anyone has said that it's created each time a scipt is run. Very likely I misunderstood something. My assumptions are only testing what I think so I know whether or not I get it. Since I now know it's created new each time something is run that makes a big difference to my understanding. It's fine to tell me to take your posts at face value but if I'm left with a question about it the face value is not a value. I'm not trying to be disrespectful however what is plain to you isn't to me. So Merry Christmas and thank you for the excellent discussion

So unless other arrays are created $args would be the only array with many elements contained within it.

Thank you

I guess not.

not following.

so, arrays within arrays?

Finally getting a clue about $args and arrays with the help of some really knowledgeable people. Thanks Scott and Rob

nm, i think i get it now

I think you are right. I'm stuck between $args and arrays. Fine, $args is an array to use or not use. Then $args[0] and $args[1] are different arrays?

Thank you all for the welcome.